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if test in bash - can't see error

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# 1  
Old 07-03-2012
if test in bash - can't see error
Hi,
I have the following script under bash

Code:
        if [ test -f "$file_name" ]; then
             echo File $file_name Not Found
        else
             echo File $file_name Found
        fi

I get the message
Code:
[: -f: binary operator expected

even the file is found; there is only one file with that name in the directory

I can't figure out what's wrong.
Thanks in advance,
# 2  
Old 07-03-2012
Hi

Either this
Code:
  if  test -f "$file_name"

or this:
Code:
if [ -f "$file_name" ]

This User Gave Thanks to guruprasadpr For This Post:
f_o_555
# 3  
Old 07-03-2012
So how the final script should be e.g. in the first case?
# 4  
Old 07-03-2012
Code:
if [ -f "$file_name" ]; then
        echo File $file_name Found
else
        echo File $file_name Not Found
fi

Alternate one ..
Code:
$ [ -f "$file_name" ] && echo "Filename $file_name Found" || echo "Filename $file_name Not Found"

This User Gave Thanks to jayan_jay For This Post:
f_o_555
# 5  
Old 07-03-2012
If I use

Code:
if [ -f "$file_name" ]; then
        echo File $file_name Found
else
        echo File $file_name Not Found
fi

then it works in the opposite direction I hae the impression, i.e. the first if detects non existing file
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