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Pattern matching in Perl

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# 1  
Old 06-30-2012
Pattern matching in Perl
Hi,

I have a list of IP, eg :
Code:
192.168.0.15
192.168.0.24
192.168.2.110
192.168.2.200

And I would like the shortest pattern who match with '192.168.0' and '192.168.2' (without the last dot and number).
Last edited by Scrutinizer; 06-30-2012 at 06:11 AM.. Reason: code tags
# 2  
Old 06-30-2012
Code:
perl -lane 'print $_ if $_=~/192.168.[02]/' filename.txt

# 3  
Old 06-30-2012
Code:
grep '^192\.168\.[02]\.' file

or
Code:
grep -w '^192\.168\.[02]' file

Last edited by Scrutinizer; 06-30-2012 at 06:18 AM..
# 4  
Old 06-30-2012
Quote:
Originally Posted by itkamaraj
Code:
perl -lane 'print $_ if $_=~/192.168.[02]/' filename.txt

Thanks itkamaraj,

To be honest i'm not very familiar with Perl in command line, I intended to use grep.
And i'm searching for something very generic, because I won't to read first numbers each time.

Something like this:
Code:
grep -P '\d+\.\d+\.\d+' filename.txt

My question is there a simpler pattern for this ?
Is possible to repeat some part of the pattern, for example: '\d+' x3 and '\.' x2
# 5  
Old 06-30-2012
Like this?

Code:
grep -E '[0-9]{3}\.[0-9]{3}\.[02]\.' inputfile

# 6  
Old 06-30-2012
Quote:
Originally Posted by elixir_sinari
Like this?

Code:
grep -E '[0-9]{3}\.[0-9]{3}\.[02]\.' inputfile

Yes thanks that's the idea, but the question it's for Perl regex not POSIX.
# 7  
Old 06-30-2012
Like this?
Code:
(\d{1,3}\.){3}

or this?
Code:
(\d+\.){3}
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