Need help for finding correct delimiter


 
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# 1  
Old 06-27-2012
Need help for finding correct delimiter

I've a series of words in the format "abc0001d" till "abc1999d".

I would like to use delimiter to cut the word from abc0001s to two words:

abc00 and 01d. Help me in finding the correct delimiter to cut in desired way.
# 2  
Old 06-27-2012
Code:
 
$ echo "abc0001d" | awk '{print substr($0,1,5)}'
abc00
$ echo "abc0001d" | awk '{print substr $0,6,3)}'
01d

This User Gave Thanks to itkamaraj For This Post:
# 3  
Old 06-27-2012
With a space as delimiter:
Code:
echo "abc0001d" | sed 's/\(.....\)\(.*\)/\1 \2/'

# 4  
Old 06-27-2012
You can use cut character option to get the result
Code:
while read line
do
        firstFour=`echo $line|cut -c1-5`
         lastThree=`echo $line|cut -c6-8`
       echo "First Four= $firstFour"
         echo "Last Three= $lastThree"
done < file

# 5  
Old 06-27-2012
Code:
$ x=abc0001d
$ first=${x:0:5}
$ echo $first
abc00
$ second=${x:5:7}
$ echo $second
01d

# 6  
Old 06-27-2012
Another way,

Code:
$ a=abc0001d
$ echo ${a:0:5}
abc00
$ echo ${a:5}
01d


EDIT : Simultaneous posting. Same solution as above.
# 7  
Old 06-27-2012
Thanks for your help Smilie
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