Error with while loop


 
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# 1  
Old 06-23-2012
Data Error with while loop

the program just prints all the command line arguments

Getting error in the program
error

Code:
./hellow: line 13: 0: command not found
./hellow: line 13: 0: command not found

below is the program

Code:
#!/bin/bash
num=$#
echo $num
if [ $# -eq 0 ]
then
    echo "No arguments are passed ."
else
  echo "total no of arguments are  $0 are $#"
fi
echo "####### starting the program"
string=hellow
i=0
while [[ `$num` > `$i` ]]
do
echo "$"$i
string=$string$$string1
(( i+=1 ))
done
echo " #### and the results are #####"
echo string= $string
echo string1 = $string1


Last edited by Scrutinizer; 06-23-2012 at 04:46 AM.. Reason: code tags
# 2  
Old 06-23-2012
What it is complaining about is the use of back ticks (`), which should be left out.
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# 3  
Old 06-23-2012
no not a problem with the ` i do think the OS is unable to find the " while " program
Any idea whether iam missing some header file like that because i am new to the shell programming i am asking this Smilie
# 4  
Old 06-23-2012
The problem is with the backticks, `. As you're new to shell scripting, perhaps you should listen to someone with more than 5700 posts?
# 5  
Old 06-23-2012
As Scrutinizer rightly said, remove the back-ticks on line 13..

With those back-ticks, your shell is assuming that the values of num and i are commands...
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# 6  
Old 06-23-2012
As per your recommendatio i used
Code:
while [ $num > $i ]

instead of using

Code:
while [[ `$num` > `$i` ]]

still facing the same problem

Code:
./hellow: line 13: [0: command not found


Last edited by Scott; 06-23-2012 at 05:30 AM.. Reason: Code tags
# 7  
Old 06-23-2012
No-one mentioned using single [ ... ], and I suspect you missed a space between [ and $num. Please use code tags, when posting code.

Use:

Code:
[[ $num > $i ]]

Or:

Code:
[ "$num" -gt "$i" ]

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