Complex bash/sed, variables and nested quotes

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# 1  
Complex bash/sed, variables and nested quotes

Ok, this one isn't for everybody, it's pretty tough and I've spent a good deal of time on it without figuring it out yet.

Can anybody get this script to work:

    cq_fname="%let outputfile="/user/cq_"$1".csv";"
    sed "29s/.*/\"$cq_fname\"/" >

$1 is usually a date. Basically, I'm trying to replace line 29 of with:
%let outputfile="/user/cq_20060104.csv";

Last edited by nocloud; 06-21-2012 at 07:31 PM.. Reason: typo
# 2  
awk 'NR==29 { print L ; next } 1' L="%let outputfile=\"/user/cq_${1}.csv\";" inputfile > outputfile

# 3  
Hi, try:
cq_fname="%let outputfile=\"/user/cq_$1.csv\";"

sed "29s|.*|$cq_fname|" >

# 4  
yup, that works!
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