sed or awk command to replace a string pattern with another string based on position of this string


 
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# 8  
Old 06-14-2012
Hi

Code:
$ sed -e 's/VALUES */&\n/;s/),/&\n/g' file |
> awk -F, '/INSERT/{for(i=1;i<=NF;i++){if ($i ~ /lastModified/){x=i;print;getline;break;}}}{y="0000-0000 00:00:00";sub(/[-0-9: ]+/,y,$x);}1'  OFS=,

# 9  
Old 06-14-2012
Try this... a bit ugly though...

Code:
awk -F"(" 'BEGIN{OFS=FS} {
split($2,t,", ");
for(i in t)
{
 if(t[i] ~ /lastModified/) 
  posit=i
}
for(i=3;i<=NF;i+=1)
{
 n=split($i,s,",")
 sub(/[-0-9: ]+/,"0000-00-00 00:00:00",s[posit])
 temp=""
 for(j=1;j<=n;j++)
 {
  if(j!=1)
   temp=temp","s[j]
  else
   temp=s[j]
 }
 $i=temp
}
print
}' inputfile


Last edited by elixir_sinari; 06-15-2012 at 03:25 AM..
This User Gave Thanks to elixir_sinari For This Post:
# 10  
Old 06-14-2012
thanks elixir you code works awesome too.. :-) :-) thanks a lot
# 11  
Old 06-19-2012
:-(
the code is not working for below table :-(

Code:
INSERT INTO `table66` (`id`, `backupReason`, `backupScope`, `backupType`, `controllingZoneId`, `delaySeconds`, `immediateBackup`, `jobType`, `maxRetries`, `performingZoneId`, `recurring`, `requestingUserId`, `schemaDifference_blob_reserved`, `schemaDifference_reserved`, `scpKey`, `startDateTime`, `storageFile`, `storageType`, `zoneScope`, `lastModified`) VALUES (2,'','user3002,user3003','USER_DATA_SINGLE',1,0,0,'BACKUP',2,NULL,0,450,NULL,NULL,'','2011-05-10 09:22:06','/var/opt/ipc/service_backup_restore','LOCAL',NULL,'2012-06-16 08:12:24');

how to fix this...
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