Shell Programming and Scripting

Can anyone assit me in completing this simple looping problem

allow the user to enter as many number as they want by using a loop. The program will keep asking the user for additional numbers until the user enters 9999. Once the user enters 9999, exit the loop and display a message telling them which number they entered was the largest of all of their entries. The number 9999 should only be used to exit the loop and should not be used as one of the entries to determine the largest number. For example, if the user enters the numbers 1, 29, 354, 231, 9999, the output should say "The largest number you entered was 354".

Code:

#!/bin/bash

largest=0

while true
do
    read -p "Enter a number (9999 to exit): " input
    (( input == 9999 )) && break
    (( input > largest )) && largest=$input
done

echo "Largest number entered was: $largest"

Thank you so much for that fast response...I am going to try it right now and see the results. I appreciate your help immensely

I followed this but I am still having an issue I keep getting this message
Enter a number (9999 to exit): I then enter my numbers 1,26,78,98,56,78
I get the response
Largest number entered was: 1,26,78,98,56,78
Can someone please tell me what I doing incorrectly?
Thanking you in advance

When it says "Enter a number (9999 to exit): ", you enter each number in a line, i.e., type a number and hit the return key (Enter) before entering next number.

your problem is that you putting the numbers in all at once and your adding commas.
Try doing:
56 (enter)
78 (enter)
44 (enter)
99 (enter)
100 (enter)
Then 9999 (enter) and you will get 100 is the largest number