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awk substr

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# 1  
Old 05-17-2012
awk substr
HI I am using awk and substr function to list out the directory names in the present working directory .

I am using below code

Code:
ls -l | awk '{ if ((substr($1,1,1)) -eq d) {print $9 }}'

But the problem is i am getting all the files and directories listed where as the requirement i wrote is for only dircetories.
I even tried below

Code:
ls -l | awk '{ if ((substr($1,1,1)) -eq 'd' ) {print $9 }}'

any help pls?

regards,
p
Last edited by Scrutinizer; 05-17-2012 at 03:28 AM.. Reason: code tags
# 2  
Old 05-17-2012
try this
Code:
# awk '{if(substr($1,1,1)=="d")print $9}'

# 3  
Old 05-17-2012
Code:
 
ls -l | awk 'substr($1,1,1)=="d"{print $9}'

# 4  
Old 05-17-2012
Code:
ls -l | awk '/^d/{print $NF}'

# 5  
Old 05-17-2012
Try like
Code:
ls -l|grep ^d

# 6  
Old 05-17-2012
Or:

Code:
ls -ld */

This User Gave Thanks to radoulov For This Post:
ni2
# 7  
Old 05-17-2012
Oh, yes of course Smilie , so then it becomes
Code:
ls -1d */

(only the name should be printed, so 1 instead of l)
Last edited by Scrutinizer; 05-17-2012 at 06:46 AM..
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