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Shell Programming and Scripting

Place , character after 3 digits from left to right in a string

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# 1  
Old 05-12-2012
Place , character after 3 digits from left to right in a string
Hi All,

Could anyone please help me, how to put ‘,' character after 3 digits from right to left count,among 17 digits sting. unix scripting
Example - I am having 12345678911234567 digits
Accepted result-- 12,345,678,911,234,567
Note- 12345678911234567 digits will be dynamic at run time, I don't know how many digit will generate may be less or more .
please help me
Thanks,
Krupa
# 2  
Old 05-12-2012
If you have 'rev' from util-linux package , it's easy:

Code:
$ echo 12345678911234567 | rev | sed 's/\([0-9][0-9][0-9]\)/\1,/g' | rev
12,345,678,911,234,567

# 3  
Old 05-12-2012
Try Perl. Regex below picked from Perl Cookbook, section 2.17.

Code:
[user@ubuntu dir]# echo 12345678911234567 | perl -lne 'chomp; $x=reverse; $x=~s/(\d\d\d)(?=\d)(?!\d*\.)/$1,/g; print (scalar reverse $x)'
12,345,678,911,234,567
[user@ubuntu dir]#

This takes care of putting commas in float numbers like 123456.789 etc.
# 4  
Old 05-12-2012
recent bash/ksh93:
Code:
printf "%'d\n" 12345678911234567

Last edited by Scrutinizer; 05-12-2012 at 07:27 AM..
This User Gave Thanks to Scrutinizer For This Post:
pravin27
# 5  
Old 05-13-2012
Scrutinizer,
Could you please explain ?
# 6  
Old 05-13-2012
Hi pravin,

The '-flag is not in the POSIX specification of the printf utility itself:printf utility: extended description, but recent bash and ksh93 appear to support this part of the POSIX specification of the printf function syntax:

Quote:
The flag characters and their meanings are:

'
[XSI] The integer portion of the result of a decimal conversion ( %i, %d, %u, %f, %F, %g, or %G ) shall be formatted with thousands' grouping characters. For other conversions the behavior is undefined. The non-monetary grouping character is used.
It depends on locale so you may need to prepend it with the desired locale.
Code:
LC_NUMERIC=en_US.UTF-8 printf "%'d\n" 12345678911234567

Last edited by Scrutinizer; 05-13-2012 at 06:32 AM..
These 4 Users Gave Thanks to Scrutinizer For This Post:
balajesuri harte mirni pravin27
# 7  
Old 05-13-2012
Code:
echo 12345678911234567 | rev | sed 's/\(...\)/\1,/g' | rev
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