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# 1  
Old 05-02-2012
awk count how many unique IPs have received that error
Hi all,

I want to write a awk script that counts unique IPs that have received one special error.
For example

Code:
25-04-2012;192.168.70.31;1254545454545417;500.0;SUCCESS
25-04-2012;192.168.70.32;355666650914;315126423993;;General_ERROR_23
30-04-2012;192.168.70.33;e;null;null;Failure
30-04-2012;192.168.70.33;e;null;null;Failure
30-04-2012;192.168.70.33;e;null;null;Failure
30-04-2012;192.168.70.33;e;null;null;Failure
30-04-2012;192.168.70.33;e;null;null;Failure
30-04-201;192.168.70.34;e;null;null;ERROR_22
30-04-2012;192.168.70.37;e;null;null;Failure.
30-04-2012;192.168.70.10;e;null;null;Failure

The result should be:

Code:
Error name              Number of unique IPs

General_ERROR_23 =     1
Failure  = 3
ERROR_22  =  1

etc...

Moderator's Comments:
Mod Comment Code tags for code, please.


Thank you very much!

Ervin
Last edited by Corona688; 05-02-2012 at 12:12 PM..
# 2  
Old 05-02-2012
Code:
awk -F";" '! E[$2,$NF]++ { U[$NF]++ } END { for(ERR in U) printf("%s\t%s\n", ERR, U[ERR]); }' filename

One of your "Failure"'s is actually a "Failure." though. Is that intentional?
This User Gave Thanks to Corona688 For This Post:
arrals_vl
# 3  
Old 05-02-2012
Your double-posting wasted a lot of my time answering a question that was already answered.

Bumping up posts or double posting is not permitted in these forums.

Please read the rules, which you agreed to when you registered, if you have not already done so.

You may receive an infraction for this. If so, don't worry, just try to follow the rules more carefully. The infraction will expire in the near future

Thank You.

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