Validating date in yyyymmdd format using PERL


 
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# 1  
Old 04-26-2012
Validating date in yyyymmdd format using PERL

Hi all,


i had a code where in user will enter a date in yyyymmdd format.. i didnt use any validation for the date and now the problem is if a user enters date instead of month after year it is proceeding with the code..

like if the date is
Code:
20120426

and if the user enters
Code:
20122604

it should not proceed!

so i need to have a check for the same.. pls help
# 2  
Old 04-26-2012
Code:
/^20\d\d(0[1-9]|1[012])(0[1-9]|[12][0-9]|3[01])$/

Beware, this regex will still validate if date entered is 20120231.
# 3  
Old 04-26-2012
hi bala,

thanks for your quick reply...

if my variable is $date then how to use this... i am beginner in perl. pls help

---------- Post updated at 02:53 AM ---------- Previous update was at 02:52 AM ----------

and this only validates for year 2012 or can i also use 1998 or something like?
# 4  
Old 04-26-2012
Code:
 
$ cat one.pl
#!/bin/perl
use Time::Local;
my $date = $ARGV[0];
$date =~ s/\s+$//;
$date =~ s/^\s*//;
my ($year, $month, $day) = unpack "A4 A2 A2", $date;
eval{ 
    timelocal(0,0,0,$day, $month-1, $year); # dies in case of bad date
    print "$date is valid\n";
} or print "Bad date: $@";

Code:
bash-3.2$ perl one.pl 20120430
20120430 is valid

bash-3.2$ perl one.pl 20120431
Bad date: Day '31' out of range 1..30 at one.pl line 8

bash-3.2$ perl one.pl 20120231
Bad date: Day '31' out of range 1..29 at one.pl line 8

bash-3.2$ perl one.pl 20120229
20120229 is valid

bash-3.2$ perl one.pl 20120230
Bad date: Day '30' out of range 1..29 at one.pl line 8

These 4 Users Gave Thanks to itkamaraj For This Post:
# 5  
Old 04-26-2012
nice one itkamaraj
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