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Shell Programming and Scripting

Removing Numbers

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# 1  
Old 04-25-2012
Removing Numbers
Hi,
Below is a scattered representation of numbers .
Code:
[0][0]1[0]  2[0]
[0][0]
  1[0]1     2[0]2  

  1[0]1      2[0]2  
[0][0]1[0]  2[0]
[0][0]
[0][0]1[0]  2[0]
[0][0]
  1[0]1      2[0]2  

[0][0]1[0]  2[0]
  1[0]1     2[0]2


I need to display only the following sequence "[0]" and delete of the remainder from the output. The output should look like
Code:
[0][0][0]  [0]
[0][0]
  [0]     [0]

  [0]      [0]  
[0][0][0]  [0]
[0][0]
[0][0][0]  2[0]
[0][0]
  [0]      [0]  

[0][0][0]  [0]
  [0]     [0]

Plz help me out
Thanks.
Last edited by Franklin52; 04-26-2012 at 03:46 AM.. Reason: Please use code tags
# 2  
Old 04-25-2012
one way sed s:[1-9]::g infile
# 3  
Old 04-25-2012
Negating RE's is always tricky and the added complexity of matching "[0]" smacks of homework.

Here is a brute force awk solution that chops out the bits you want ([0] and space).
Code:
awk '{while(match($0, "[[]0]| ")) {
    printf "%s", substr($0, RSTART, RLENGTH)
    $0=substr($0,RSTART+RLENGTH);
    } printf "\n"}' infile

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