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question about awk

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# 1  
Old 04-25-2012
question about awk
Code:
Mike Harrington:(510) 548-1278:250:100:175                   
  Christian Dobbins:(408) 538-2358:155:90:201                   
  Susan Dalsass:(206) 654-6279:250:60:50 
  Archie McNichol:(206) 548-1348:250:100:175 
  Jody Savage:(206) 548-1278:15:188:150 
  Guy Quigley:(916) 343-6410:250:100:175 
  Dan Savage:(406) 298-7744:450:300:275 
  Nancy McNeil:(206) 548-1278:250:80:75 
  John Goldenrod:(916) 348-4278:250:100:175 
  Chet Main:(510) 548-5258:50:95:135 
  Tom Savage:(408) 926-3456:250:168:200 
  Elizabeth Stachelin:(916) 440-1763:175:75:300

How do you print the names who contributed between 90 and 150 dollars in the third month?

This is what I've tried.


Code:
awk -F: '$5 >= 90,150  {print $1}' information

# 2  
Old 04-25-2012
ah can't use two numbers in 1 comparison operation like that...

Code:
$ awk -F: '($5 >= 90)&&($5 <= 150){print $1}' info
  Jody Savage
  Chet Main

This User Gave Thanks to neutronscott For This Post:
JA50
# 3  
Old 04-25-2012
what's the "third month"?
Code:
awk -F: '$5 >= 90 && $5<=150  {print $1}' information

This User Gave Thanks to vgersh99 For This Post:
JA50
# 4  
Old 04-25-2012
Third month is the last number. Thanks guys.
# 5  
Old 04-25-2012
Code:
awk -F: '$NF>=90 && $NF<=150{print $1}' input.txt

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