Here is the code:
my question is: what will @allwords now contain, or how would the entries in the @allwords array be different after this manipulation?
Thank you!!
I am trying to understand more about this array.
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Last edited by jim mcnamara; 04-19-2012 at 12:34 AM..
Reason: [mod]Please use standard fonts in code blocks and code tags[/mod]
your array @allwords is empty hence foreach loop would never execute
you will still have an empty hash after the foreach loop
thus the last statement won't cause any difference and @allwords would still be empty
if you had some entries in @allwords say,
the foreach loop will assing each element of the array @allwords as a key to %seen hash and each key would have 1 as it's value i.e.,
however, on the last iteration when $curr is a again, your hash already has a key a with value as 1, so it won't allow a duplicate entry and last element of @allwords would be discarded
keys %seen would return ('a','b','c','d') and assign it to @allwords
hence, in short your code here would remove any duplicate entries in an array
Njoy!!
This User Gave Thanks to sam05121988 For This Post:
your array @allwords is empty hence foreach loop would never execute
you will still have an empty hash after the foreach loop
thus the last statement won't cause any difference and @allwords would still be empty
if you had some entries in @allwords say,
the foreach loop will assing each element of the array @allwords as a key to %seen hash and each key would have 1 as it's value i.e.,
however, on the last iteration when $curr is a again, your hash already has a key a with value as 1, so it won't allow a duplicate entry and last element of @allwords would be discarded
keys %seen would return ('a','b','c','d') and assign it to @allwords
hence, in short your code here would remove any duplicate entries in an array
Njoy!!
THANK YOU!!!
---------- Post updated at 11:39 ---------- Previous update was at 11:39 ----------
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