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# 1  
Old 04-04-2012
Question about grep
is there anyway i can ask grep to only get the first line?
as in the top command line

line 1 <-- just grep this line
line 2
line 3

---------- Post updated at 04:24 PM ---------- Previous update was at 04:19 PM ----------

nvm.. found out that i can do it with

Code:
|head

# 2  
Old 04-04-2012
If you only want to search the first line of a file, you could do:
Code:
head -1 file | grep pattern

as opposed to getting the first line of the search results for the whole file, which would be
Code:
grep pattern file | head -1

(although you might be able to do either just with grep, depending on the options your implementation has)
# 3  
Old 04-04-2012
Code:
head -1 filename | grep "string"

However, this is faster for large files:
Code:
sed -n '1,1p;1q' bigfile | grep "string"

Last edited by methyl; 04-04-2012 at 06:41 PM.. Reason: improvement
This User Gave Thanks to methyl For This Post:
Nick1097
# 4  
Old 04-04-2012
ah great... hmm sed , time to look up sed

btw the size of directory without sub is
Code:
du -S

that's what i got from the linux library i've been reading.
but for some reason when i type that in my system it doesnt work.. maybe cause im using bourne shell?
there should be an alternate way right? can give me a hint?
# 5  
Old 04-05-2012
"doesn't work" is not exactly descriptive. You get an error message, blank output, or what?
This User Gave Thanks to CarloM For This Post:
Nick1097
# 6  
Old 04-05-2012
@ Carlom - yes as balajesuri said, it's not supported. no such option

@balajesuri , oh i see, need to write that down for future reference.

Thanks again CarloM and balejesuri
# 7  
Old 04-05-2012
Code:
sed '/string/!d;q' inputfile
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