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Shell Programming and Scripting

total up 1st value

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# 1  
Old 04-03-2012
total up 1st value
Code:
for p in $@; 
do size = '(ls -RFsh $dval | grep \/$ | awk '{ print $1 }' '
((totalsize = totalsize + size))
echo "$size"
done;
echo "$totalsize "

with that i got size not found [no such file / directory]
anyone got any idea why? Smilie

im trying to add up the size of the directory and print up total
# 2  
Old 04-03-2012
can you post the output of below command

Code:
 
ls -RFsh $dval

# 3  
Old 04-03-2012
Documents/Music:
Documents:
total 16k
4.0k Music/ 4.0k Pictures/ 4.0k Templates/ 4.0k Videos/

Documents/Music:
total 0

Documents/Pictures:
total 0

Documents/Templates:
total 0

Documents/Videos:
total 0
# 4  
Old 04-03-2012
so, you want to sum the total values ?

Code:
total 16k
total 0
total 0
total 0
total 0

# 5  
Old 04-03-2012
with grep \/$ it i will print

4.0k
4.0k
4.0k
4.0k

but size doesnt record it :S

---------- Post updated at 04:50 AM ---------- Previous update was at 04:49 AM ----------

yeh, but im suppose to record selected file size and total only those etc
in Document if i wan Music and Picture only the total size will be 8

---------- Post updated at 04:51 AM ---------- Previous update was at 04:50 AM ----------

was gonna do another grep just to pick up selected arguments
# 6  
Old 04-03-2012
are you trying to calculate the directory size ? ( which the path was passed as argument ?)
# 7  
Old 04-03-2012
yeh

was gonna do ./calculate -d Documents -t Music Picture
this command will printout total size of Music + Picture directory
without using du tho
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