delete a row with a specific value at a certain column


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# 1  
delete a row with a specific value at a certain column

Hi,

I want to delete rows that have 0 at column 4.

The file looks like this:

Code:
chr01   13	61	2
chr01   65	153	0
chr01   157	309	1
chr01   313	309	0
chr01   317	469	1
chr01   473	557	0

I want to delete all rows with a 0 at column 4

Code:
chr01   13	61	2
chr01   157	309	1
chr01   317	469	1

Thanks
# 2  
Code:
awk '$4 != 0' inputfile

# 3  
try this
Code:
awk -F " " '{ if ( $4 != 0 ) print $0 }' infile

@balajesuri yours is much trimmed Smilie
# 4  
Quote:
Originally Posted by 47shailesh
try this
Code:
awk -F " " '{ if ( $4 != 0 ) print $0 }' infile

@balajesuri yours is much trimmed Smilie
Few points to observe:
1. awk already separates the fields based on whitespaces. So, -F " " is really not necessary.
2. awk follows this: condition {action} by default. So an if-statement can be masked as condition{action}, unless its use is inevitable.
3. awk prints the current line by default. So print $0 is redundant.
4. Implementing all the above points you get what is in post #2 above Smilie

Well, to shorten it even more, we can say: Smilie
Code:
awk '$4' inputfile


Last edited by balajesuri; 03-30-2012 at 02:13 AM..
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