Help with Shell Script


 
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# 1  
Old 03-29-2012
Data Help with Shell Script

I need to copy multiple files from/to other directory, but i need to organize them by dates.
The command is like this:

Code:
cp -fp $(ls -gto --full-time | grep 2012-03-21 | cut -c 57-108) ../Destino/2012/03/21/

but i need to create repeat this command for each date, like this:

Code:
cp -fp $(ls -gto --full-time | grep 2012-03-19 | cut -c 57-108) ../Destino/2012/03/19/
cp -fp $(ls -gto --full-time | grep 2012-03-20 | cut -c 57-108) ../Destino/2012/03/20/
cp -fp $(ls -gto --full-time | grep 2012-03-21 | cut -c 57-108) ../Destino/2012/03/21/

i attempted to make a loop using for but doesn't worked, anyone have a suggestion?
all the files have the same extension, but their names are composed by random numbers, and this command has worked fine, my ideas has exhausted.
Smilie

And sorry for my poor English.
# 2  
Old 03-29-2012
I am assuming you just want to copy files and not directories, try this
Code:
dt=`date '+%Y/%m/%d'`
mkdir -p ../Destino/$dt
cp -fp $(find . -mtime -1 -type f | awk -F "/" '{print $NF}') ../Destino/$dt

# 3  
Old 03-29-2012
Please post a representative sample of ls -gto --fulltime .
Do any of your filenames contain space characters?
# 4  
Old 03-29-2012
Quote:
Originally Posted by 47shailesh
I am assuming you just want to copy files and not directories, try this
Code:
dt=`date '+%Y/%m/%d'`
mkdir -p ../Destino/$dt
cp -fp $(find . -mtime -1 -type f | awk -F "/" '{print $NF}') ../Destino/$dt

It's doesn't worked for me.

Quote:
Originally Posted by methyl
Please post a representative sample of ls -gto --fulltime .
Do any of your filenames contain space characters?
Code:
-bash-4.1$ ls -gto --full-time
total 92
-rwxrwxrwx. 1  8506 2012-03-22 11:59:35.343379200 -0300 33120330290688000152550000001426791634726526-nfe.xml
-rwxrwxrwx. 1  8635 2012-03-21 16:53:57.939979500 -0300 33120330290688000152550000001423161507994592-nfe.xml
-rwxrwxrwx. 1 10298 2012-03-21 15:50:39.661979500 -0300 33120330290688000152550000001423141008578203-nfe.xml
-rwxrwxrwx. 1 12357 2012-03-21 12:06:39.467400000 -0300 33120330290688000152550000001422941231160022-nfe.xml
-rwxrwxrwx. 1 11184 2012-03-20 10:22:58.387596900 -0300 33120330290688000152550000001419341011673085-nfe.xml
-rwxrwxrwx. 1  8482 2012-03-20 10:06:56.862996900 -0300 33120330290688000152550000001419331947121936-nfe.xml
-rwxrwxrwx. 1  7629 2012-03-19 16:11:18.646997000 -0300 33120330290688000152550000001416431560981105-nfe.xml
-rwxrwxrwx. 1  8133 2012-03-19 15:13:07.492397000 -0300 33120330290688000152550000001416381402258321-nfe.xml

-----

I need to copy the files according with they creation/modification date, the modification/creation time is the same for each file and never will change, for example, the file created on 2012-03-19, need to be copied to ../Destino/2012/03/19/, and i can copy the file with that command:
Code:
cp -fp $(ls -gto --full-time | grep 2012-03-21 | cut -c 57-108) ../Destino/2012/03/21/

I want to make one script like that:
Code:
var1=something
var2=something
for filename in *.xml
do cp -fp $(ls -gto --full-time | grep $var1 | cut -c 57-108) ../Destino/$var2
done

I don't have experience with Shell Script, and exhausted all of my ideas for solve that, i need this for my work or i will need to copy the files 1 by 1, alone Smilie Smilie

Last edited by Hitokiri; 03-29-2012 at 03:07 PM.. Reason: added information
# 5  
Old 03-29-2012
this may be not the best but it will do what you need. and adjust ../Destino/$fldr such that it's a valid absolute/relative path
Code:
ls -gto --full-time | awk -F " " '{print $4}' | sort | uniq | awk NF | while read dt 
    do
        cp_str=`ls -gto --full-time | grep $dt | awk -F " " '{print $NF}' | tr -s "\n" " "` 
        fldr=`echo $dt | sed s:-:/:g
        mkdir -p ../Destino/$fldr 2>/dev/null 
        cp $cp_str ../Destino/$fldr  2>/dev/null
    done


Last edited by 47shailesh; 03-30-2012 at 12:12 AM.. Reason: added code to remove one blank input
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