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Passing variable with *

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# 1  
Old 03-28-2012
Passing variable with *
Hi Folks,
I would like to pass a variable with a wild card in an argument. My script works if I don't use a wildcard but fails when I use *. I want to use the script like:
scriptname -F <filename*>
Code:
@ i = 0
while ($i <= ${#argv})
   switch ($argv[$i])
    case -F:
        set j = `echo $i +1 |bc`
        set file = `echo $argv[$j]`
    endsw
@ i++
end

I want my $file = filename*, that is with wild card.
Thanks in advance.
# 2  
Old 03-28-2012
You can try putting the variable in double-quotes " ", but CSH's quoting functionality is extremely perplexing. See csh programming considered harmful.
# 3  
Old 03-28-2012
I already tried the option of using double/single quotes but it doesn't work.

---------- Post updated at 12:12 PM ---------- Previous update was at 11:39 AM ----------

I had to use BASH which allows you to pass variable with wild card provided if you use double quotes.

Thanks for you help.
This User Gave Thanks to dixits For This Post:
Corona688
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