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Compare filename to file folder

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# 1  
Old 03-28-2012
Compare filename to file folder
Hi. I have a problem, could you help me ?
Situation:
there are alot of files in directory_1, with the names like "notneeded1blabla.bla", "notveryneededblabla.gla".
there is directory_2 that has directories with names like that: "bla_needed1", "blab_veryneeded".
What i need so much is to place all files that contains
"needed1" to put in "bla_needed1" directory and
"veryneeded" -> "blab_veryneeded" directory

i've found alot of scripts that compare characters in one string to another but nothing that suites my case.
# 2  
Old 03-28-2012
Try this
Please test this before using in the real world.

Code:
 
#!/bin/ksh
DIR1=dir1
DIR2=dir2
MATCHSTR1=str1
MATCHSTR2=str2
#MATCHST1 and MATCHSTR2 should be exclusive of each other.
#meaning when searching for MATCHST1, MATCHSTR2 should not come.
`mv *${MATCHSTR1}* DIR1`
`mv *${MATCHSTR2}* DIR2`
exit 0

# 3  
Old 03-29-2012
Thanks but I already have a script like this. Its not exactly what i am looking for.

There are alot of those different directories, more than 150 and it keeps growing. Manually adding DIR and MATCHSTR is not what i need. Automating such work should be the best solution, and thats what i am looking for. Unfortunately i am no programmer so i can't make a script like this.

Script should look at the file name then look at directory and if it found matches for string that contains 8-10 characters in a raw put that file in the respective directry and repeat for another file, if directory not found search for another one until found.
# 4  
Old 03-30-2012
Try the given code
Please make sure to test this before using it in live environments.

Code:
 
#!/bin/ksh
SRCDIR=./src
DSTDIR=./dest
for matchstr in `ls -lrt ${DSTDIR} | grep ^d | awk '{ print length($9) "," $9; }' | sort -r -k 1,1 | cut -d"," -f2`
do
  for fil in `ls ${SRCDIR}`
  do
    ismatch=`echo ${fil} | grep -c ${matchstr}`
    if [[ ${ismatch} -gt 0 ]]
    then
      mvcmd="mv ${SRCDIR}/${fil} ${DSTDIR}/${matchstr}/"
      `${mvcmd}`
    fi
  done
done
exit 0

This User Gave Thanks to arun.ijhs.klm For This Post:
sw_and
# 5  
Old 03-30-2012
Alternatively test and try this:
Code:
for dir in directory_2/*/
do 
  dir=${dir%/}
  for file in directory_1/*"${dir##*_}"*
  do 
    echo mv "$file" "$dir"
  done
done

If satisfied with the results then you can test and remove the echo statement
This User Gave Thanks to Scrutinizer For This Post:
sw_and
# 6  
Old 03-30-2012
@Scrutinizer: Good compact code.

Please find two observations below.

Issue 1:
Let us say there are two directories in the destination with the below names.
TEST
RETEST

And two files in source directory with the file names 'DoTEST.001' and 'DoRETEST.001'

If the first pattern check is TEST, both the files would be moved to TEST directory. Ideally 'DoRETEST.001' should be moved to RETEST directory.

Issue 2:
There is a limit to the number of characters that an unix command can contain.

If there are multiple files matching the pattern and the command (mv command) length exceeds the limit, it would go into error.
# 7  
Old 03-30-2012
Thank you..
Issue 1: Then one could try Do"${dir##*_}".* for example, the OP would need to improvise a little, or if possible, use distinct directory names (like in the OP's post)..
Issue2: Yes, that is why the script is moving 1 file at a time. If you are referring to "for", this is a shell keyword, there is no limit...
Last edited by Scrutinizer; 04-02-2012 at 06:40 AM..
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