List unique values and count instances in .csv file


 
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# 1  
Old 03-20-2012
List unique values and count instances in .csv file

I need to take the second column of a .csv file and count the number of instances of each unique value in that same second column. I'd like the output to be value,count sorted by most instances. Thanks for any guidance!

Data example:

317476,317756,0
816063,318861,0
313123,319091,0
317020,318466,0
516779,166445,1
319020,318466,0
316729,316483,0
631299,317306,0
313933,317306,0
168032,318032,0
160183,317722,0
917710,312593,0
316559,317756,0
319424,317756,0
# 2  
Old 03-20-2012
Try:
Code:
awk -F, '{A[$2]++}END{for(i in A)print i,A[i]}' OFS=, infile | sort -t, -k2,2rn

Code:
317756,3
317306,2
318466,2
166445,1
312593,1
316483,1
317722,1
318032,1
318861,1
319091,1

This User Gave Thanks to Scrutinizer For This Post:
# 3  
Old 03-20-2012
Where do I specify the input and output filenames?
# 4  
Old 03-20-2012
I'd be tempted to use a Perl hash keyed on the values and sorted by value. eg.
Code:
perl -e 'while(<>){@record=split/,/,$_;$count{$record[1]}++;}for $key (reverse sort {$count{$a}<=>$count{$b}} keys %count){print "$key => $count{$key}\n"}'    tmp.dat

# 5  
Old 03-20-2012
Looks great so far. I'm just going to verify the data against something else. Thanks for the quick reply!
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