String manipulation


 
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# 1  
Old 03-19-2012
String manipulation

Hello

Could you help with small script:
How to split string X1 into 3 string
String X1 can have 1 or many strings

Code:
X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'

This is output which I want to have:
Code:
Z1='A1:B1:C1:D1'
Z2='A2:B2:C2:D2'
Z3='A3:B3:C3:D3'

# 2  
Old 03-19-2012
Quote:
Originally Posted by vikus
How to split string X1 into 3 string
String X1 can have 1 or many strings
<snip...>
can you tell more about the string and what to do?
split after every hex value above D1?
split after every table location pointing to 4th column?
# 3  
Old 03-19-2012
One way would be..
Code:
[mkt@ michael]$ X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'
[mkt@ michael]$ Z1=$(echo $X1 | cut -d: -f1-4)
[mkt@ michael]$ Z2=$(echo $X1 | cut -d: -f5-8)
[mkt@ michael]$ Z3=$(echo $X1 | cut -d: -f8-)

# 4  
Old 03-19-2012
@daWonderer split after every table location pointing to 4th column.
@michaelrozar17 this will not work if i will have more if i have more strings
# 5  
Old 03-19-2012
BASH

Hi,

I think the below script may full fill your requirement.

Code:
#! /bin/bash
c=1
info="A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3:A4:B4:C4:D4:A5:B5:C5:D5"
for i in `echo $info | sed 's/\([A-Z0-9]*\):\([A-Z0-9]*\):\([A-Z0-9]*\):\([A-Z0-9]*\):/\1:\2:\3:\4\n/g'`
do
   eval X$c="$i"
   let c=$c+1
done
let c=$c-1
for j in `seq 1 $c`;
do
   eval echo \$X$j;
done

Cheers,
RangaSmilie
# 6  
Old 03-19-2012
it's possible do with awk ?
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