Joining multi-line output to a single line in a group


 
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# 1  
Old 03-07-2012
MySQL Joining multi-line output to a single line in a group

Hi,

My Oracle query is returing below o/p

Code:
---------------------------------------------------------- 
Ins    trnas             value 
a      lkp1               x 
a      lkp1               y 
b      lkp1               a 
b      lkp2               x 
b      lkp2               y 
------------------------------------ 
now I want to convert this o/p  to  below o/p using perl script
 
ins trans    value 
a   lkp1       xy 
b   lkp1       a 
b   lkp2       xy


Thanks
gvk25
# 2  
Old 03-07-2012
Code:
perl -lane 'if($.==1){print;next}; $x{"$F[0] $F[1]"} .= $F[2]; END{for (sort keys %x){print "$_ $x{$_}"}}' inputfile

# 3  
Old 03-07-2012
I am storing my o/p of the query in an array,I want to use an array instead of inputfile.
Dow we have any other way to implement above logic

Code:
@ins=(a,a,b,b,b); @trans=(lkp1,lkp1,lkp1,lkp1,lkp2,lkp2) @value(x,y,a,x,y)


Last edited by gvk25; 03-07-2012 at 04:53 AM..
# 4  
Old 03-07-2012
Code:
#! /usr/bin/perl -w
use strict;

my @ins   = qw ( a    a    b    b    b    );
my @trans = qw ( lkp1 lkp1 lkp1 lkp2 lkp2 );
my @value = qw ( x    y    a    x    y    );
my %x;
my $prev = "";

for (0..$#ins) {
    if ($prev eq "$ins[$_] $trans[$_]") {
        print "$value[$_]";
    }
    else {
        print "\n$ins[$_] $trans[$_] $value[$_]";
        $prev = "$ins[$_] $trans[$_]";
    }    
}

This User Gave Thanks to balajesuri For This Post:
# 5  
Old 03-07-2012
thanks very much for you help

---------- Post updated at 03:16 PM ---------- Previous update was at 03:08 PM ----------

I want to call a funtion with the value of each group how can I acheive this


I mean after concatenation of particular group values

Code:
i.e  group 1    a  lkp1   xy 
                    sub test(xy)
     group 2    b  lkp2   a  
                    sub test(xy)
     group 3    b lkp2  xy
                     sub test (xy)
 
and so ....
 
a lkp1 xy
b lkp1 a
b lkp2 xy

# 6  
Old 03-07-2012
Code:
awk 'NR>1{x=$1 FS $2;n=NR}!b[x]++{b[n]=x}{a[x]=((x in a)?a[x]:z)$NF}END{for(i=0;++i<=n;) if(i in b) print b[i],a[b[i]]}' yourfile

# 7  
Old 03-07-2012
Can you explain me the code what you are doing

---------- Post updated at 03:22 PM ---------- Previous update was at 03:20 PM ----------

hi Balaji can you explain the logic which you have implemented.
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