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delete first 2 characters for each line, please help

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# 1  
Old 02-10-2012
delete first 2 characters for each line, please help
hi,

./R1_970330_210505.sard
./R1_970403_223412.sard
./R1_970626_115235.sard
./R1_970626_214344.sard
./R1_970716_234214.sard
...
...
...

for these strings, i wanna remove the ./ for each line
how can i do that?

i know it could possibly be done by sed, but i really have not idea how to use that command

thanks a lot!
# 2  
Old 02-10-2012
You don't need sed for such a simple task:
Code:
cut -c3- file

This User Gave Thanks to bartus11 For This Post:
sunnydanniel
# 3  
Old 02-10-2012
For completeness, here is the sed command:
Code:
sed 's/..//' file

This User Gave Thanks to Scrutinizer For This Post:
sunnydanniel
# 4  
Old 02-11-2012
AWK one
Code:
awk -F"/" '{print $2}' urfile

Last edited by Franklin52; 02-11-2012 at 11:45 AM.. Reason: Please use code tags for data and code samples, thank you
# 5  
Old 02-11-2012
sed only ..

Code:
  
[root@SKS Shirish]# echo "123 shirish" > a
[root@SKS Shirish]# cat a
123 shirish
[root@SKS Shirish]#  sed -i 's/^.\{2\}//g'   a
[root@SKS Shirish]# cat a
3 shirish
[root@SKS Shirish]#

Hope It will help u bit ...

FOR YOUR CONTENT ...

Code:
[root@SKS Shirish]# cat ab
./R1_970330_210505.sard
./R1_970403_223412.sard
./R1_970626_115235.sard
./R1_970626_214344.sard
./R1_970716_234214.sard
[root@SKS Shirish]# sed -i 's/^.\{2\}//g' ab
[root@SKS Shirish]# cat ab
R1_970330_210505.sard
R1_970403_223412.sard
R1_970626_115235.sard
R1_970626_214344.sard
R1_970716_234214.sard
[root@SKS Shirish]#

--Shirish Shukla
Last edited by Shirishlnx; 02-11-2012 at 12:38 PM..
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