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How to display the line number of file while searching for a pattern

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# 1  
Old 02-06-2012
How to display the line number of file while searching for a pattern
Code:
awk 'BEGIN{IGNORECASE=1} /error|warning|exception/  { ++x } END { print x }' filename

The above command returning the number of times the pattern present in the file. But I want the the line number as well. please help me out
Last edited by methyl; 02-06-2012 at 12:25 PM.. Reason: please use code tags
# 2  
Old 02-06-2012
Hi arukuku,

But there could be many line numbers. How do you want the output?

Regards,
Birei
# 3  
Old 02-06-2012
The builtin awk variable NR stands for the line no...so knowing that you can add some code to your awk script to print out NR whenver the desired pattern is matched...
# 4  
Old 02-06-2012
Birei , I want the line number for which the pattern matches.
Sham rock, Ya tryin to do that. But not able to do it . I want to do it in awk only
# 5  
Old 02-06-2012
where it says ++x you can also print the line number (NR)
# 6  
Old 02-06-2012
Code:
grep -n 'pattern'

# 7  
Old 02-06-2012
Good thought, but we would need ERE for different choices and we need to ignore case, so grep -Ein 'pattern' would be the ticket, but then we would not get the total number of matches, although we could run it through wc -l separately in case we'd really need to know..
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