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Variable print problem

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# 1  
Old 01-31-2012
Variable print problem
Hi,
I'm facing some problem with printing the values in the variables

I have passed all the database values into the variable, but when i echo the variable i get the values printed in one line
Code:
var=`echo <query> | database`
echo $var
or 
awk 'BEGIN {printf("%s\n","'"${var}"'")}'

this prints
Code:
table1 <value> table2 <value> table3 <value> table4 <value>

But the above needs to be printed as
Code:
table1 <value>
table2 <value>
table3 <value> and so on

Can anyone please help me

Moderator's Comments:
Mod Comment Please use next time code tags for your code and data
# 2  
Old 01-31-2012
It would help to see the output from
Code:
echo <query> | database

Your problem is that Shell Environment Variables are not files and the line break character is lost.

But. assuming that the database writes the output in pairs (with a line terminator), we need to read them as pairs:
Code:
echo <query> | database | while read table value
do
       echo "${table} ${value}"
done

# 3  
Old 01-31-2012
Thanks Methyl

The output i get from the command is

Code:
echo <query> | database

table1 <value>
table2 <value>
table3 <value>

but if i pass the values to the variable then i'm getting

Code:
table1 <value> table2 <value> table3 <value> table4 <value>

Last edited by methyl; 01-31-2012 at 02:09 PM.. Reason: please use code tags
# 4  
Old 01-31-2012
Try echo "$var". Without that, shell expansion is going to squeeze all the whitespace together.
# 5  
Old 01-31-2012
Try my solution from post #2 . Should work.
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