How to start reading from the nth line till the last line of a file.


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# 1  
How to start reading from the nth line till the last line of a file.

Hi,
For my reuirement, I have to read a file from the 2nd line till the last line<EOF>.

Say,
Code:
I have a file as test.txt, which as a header record in the first line followed by records in rest of the lines.
 
for i in `cat test.txt`
{
echo $i
}
 
While doing the above loop, I have read from the 2nd line till last line<EOF> skipping the 1st line (header)

Can someone please help in this?
# 2  
Maybe there is an easier/better/efficient way to do this. For the moment, try this:


Code:
grep -v `head -1 /tmp/test` /tmp/test

Here is the output:

Quote:
Test blah
Test BLah1
Test BLAH 2
my /tmp/test has the following lines:

Quote:
$ cat /tmp/test
##Header

Test blah
Test BLah1
Test BLAH 2
# 3  
Thanks!
# 4  
Much faster with "sed". Also by using "while read" rather than "for" we preserve each record intact:
Code:
sed -n '2,$ p' test.txt | while read line
do
         echo "${line}"
done

Note the double quotes round the string variable $line.
This User Gave Thanks to methyl For This Post:
# 5  
or awk:

Code:
awk 'NR>8' file | while read LINE
do
        ...
done

Also see useless use of cat and useless use of backticks. You should NOT be reading files by `cat`, that has many problems and corners.
This User Gave Thanks to Corona688 For This Post:
# 6  
Guys Thanks a lot!! Will no more use cat...
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