I have a file with hundreds of lines that looks something like this:
I'm trying to list all the row numbers, except for "bad" lines with the following criteria:
a) row numbers in which the last column meets some threshold, for instance >1.5
AND
b) The next 3 rows after the row that is excluded in a)
For instance, in the sample above, the desired output would be:
So far, I'm able to get the "bad" lines with:
but I'm a little lost on how to get the opposite, or "good" lines. This also can be redundant, and it prints extra row values if the last row meets the "bad" line criteria. It seems like the wrong direction to go.
Would I have to go through the file twice, once to flag "bad" lines and again to print "good" lines (by excluding "bad" lines)?
Hope this makes sense. Thanks for the help!
Last edited by david_seeds; 01-18-2012 at 07:09 PM..
Reason: typo in my awk example
When your data is consistent it is easy to use awk with multiple lines like this. Can we please make this portable so I can use this in both RHEL and AIX?
awk '{RS="/directory1" } $7 ~ /drwxr-xr-x/ {print $1 " " $7}' file
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