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Printing empty subdirs before delete

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Top Forums Shell Programming and Scripting Printing empty subdirs before delete
# 1  
Old 01-11-2012
Printing empty subdirs before delete
I am using following code to delete all the empty sub dirs from the inputted dir $1.
Before deleting empty dirs, I want to print those dirs which are going to be deleted.
Can this be done with little modification in following code

Code:
#!/bin/sh
if [ $1 -eq '' ]; then
echo "Searching '$1' dir for empty subdirs \n"
fi
find $1 -type d | xargs rmdir -ps
echo "All empty subdirs in '$1' are deleted successfully"

Last edited by radoulov; 01-11-2012 at 02:26 AM.. Reason: Code tags!
# 2  
Old 01-11-2012
Code:
$ find $1 -type d -print -exec rmdir -ps {} \;

# 3  
Old 01-11-2012
Thanks jayan_jay,
This works fine but one problem.
I have dir structure ./a/b/c/d/e/f/g/h ...it displays all of them even if they are not empty...

Quote:
Originally Posted by jayan_jay
Code:
$ find $1 -type d -print -exec rmdir -ps {} \;

# 4  
Old 01-11-2012
check whether your find supports -empty
# 5  
Old 01-11-2012
No it doesnt (:-
I have modified script as below
Code:
#!/bin/sh
if [ $1 -eq '' ]; then
  echo "Searching '$1' dir for empty subdirs \n"
fi
echo "Following  empty dirs are going to be deleted \n"
ls -Rl * | awk '/total 0/{print last}{last=$0}'
find $1 -type d | xargs rmdir -ps
echo "All above empty subdirs in '$1' have been deleted successfully"

Now I need one more help. I need to display " No empty dir exists " is there are no empty dirs.
How to incorporate it in this script.
Thanks,
Ajay
Quote:
Originally Posted by itkamaraj
check whether your find supports -empty
Last edited by Franklin52; 01-11-2012 at 05:01 AM.. Reason: Please use code tags for code and data samples, thank you
# 6  
Old 01-11-2012
printing empty subdirs before delete
just tried to tweak jayan code , give it try :
Code:
find $1 -type d -size 0 ac -print -exec rmdir -ps {} \;

SmilieSmilie


Moderator's Comments:
Mod Comment How to use code tags
Last edited by Franklin52; 01-11-2012 at 05:02 AM.. Reason: Please use code tags for code and data samples, thank you
# 7  
Old 01-12-2012
This is not working . I am getting error
Code:
find: bad option ac
find: path-list predicate-list

Quote:
Originally Posted by mann2719
just tried to tweak jayan code , give it try :
Code:
find $1 -type d -size 0 ac -print -exec rmdir -ps {} \;

SmilieSmilie


Moderator's Comments:
Mod Comment How to use code tags
---------- Post updated 01-12-12 at 12:24 AM ---------- Previous update was 01-11-12 at 04:21 AM ----------

Is there anyway to ls for $1 dir ...currently below ls is feting o/p from current dir.
I want to execute it for $1 dir

Code:
 ls -Rl * | awk '/total 0/{print last}{last=$0}'

Quote:
Originally Posted by ajaypatil_am
No it doesnt (:-
I have modified script as below
Code:
#!/bin/sh
if [ $1 -eq '' ]; then
  echo "Searching '$1' dir for empty subdirs \n"
fi
echo "Following  empty dirs are going to be deleted \n"
ls -Rl * | awk '/total 0/{print last}{last=$0}'
find $1 -type d | xargs rmdir -ps
echo "All above empty subdirs in '$1' have been deleted successfully"

Now I need one more help. I need to display " No empty dir exists " is there are no empty dirs.
How to incorporate it in this script.
Thanks,
Ajay
---------- Post updated at 05:07 AM ---------- Previous update was at 12:24 AM ----------

I actually require script as follows.

STEP 1 count number of empty dirs
STEP 2 if number of empty dirs is 0 echo "There are no empty dirs in this dir"
exit
else
print number of dirs
display all empty dir name
STEP 3 delete all empty dirs

Can any expert here help

Thanks,
A
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