zero padding problem (bash)


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# 1  
Java zero padding problem (bash)

Hi there,

I need to loop some values,

Code:
for i in $(seq $first $last)
do
  does something here
done

for $first and $last, i need it to be of fixed length 5. so if the input is 1, i need to add zeros in front such that it becomes 00001. It loops till 99999 for example, but the length has to be 5.

eg 00002, 00042, 00212, 012312 and so forth.

any idea on how i can do that? thanks!
# 2  
Code:
$> read first
432
$>printf "%05d\n" $first
00432

# 3  
Code:
for i in {00001..99999}
do
     does something here
done

or
Code:
for i in $(seq -w ${first} ${last})
do
     does something here
done

# 4  
Hi.

Similarly to c:
Code:
#!/usr/bin/env bash

# @(#) s1	Demonstrate c-like for-loop in bash.

pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C

pe
first=17
last=21
for (( i=first ; i<=last ; i++ ))
do
  printf "%05i\n" $i
done

exit 0

producing:
Code:
% ./s1

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0.8 (lenny) 
GNU bash 3.2.39

00017
00018
00019
00020
00021

See man bash for details ... cheers, drl
# 5  
Another alternative,
Code:
for i in `seq -f%05g $first $last`

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