printing patterns


 
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# 1  
Old 12-28-2011
printing patterns

I have the following file :

1 2 3 4 5
6 7 8 9 0
9 8 7 6 5
4 3 2 1 0

0 1 2 3 4

Write scripts to
get the following outputs :

A)

1
7
7
1
4

B)

1 2 3 4 5
6 7 8 9
9 8 7
4 3
0

please give a solution...
# 2  
Old 12-28-2011
Sounds like homework... any trials?...

a clue!...
Code:
root@bt:/tmp# awk '...' infile
1 2 3 4 5
6 7 8 9
9 8 7
4 3
0
root@bt:/tmp# awk '...' infile
1
7
7
1
4

--ahamed
# 3  
Old 12-28-2011
please try using arrays or search and cut options

---------- Post updated at 12:18 AM ---------- Previous update was at 12:17 AM ----------

use awk
# 4  
Old 12-28-2011
# 5  
Old 12-28-2011
solutions

this ids my idea i got the result
ans B)
#!/bin/bash
cat p | sed -n 1p |cut -d " " -f1-5
cat p | sed -n 2p |cut -d " " -f1-4
cat p | sed -n 3p |cut -d " " -f1-3
cat p | sed -n 4p |cut -d " " -f1-2
cat p | sed -n 6p |cut -d " " -f1
ans A)
#!/bin/bash

for (( i=1; i<=4; i++ ))
do
cat p | sed -n $i\p | cut -d " " -f $i
done
cat p | sed -n 6p | cut -d " " -f 5

can anyone do the ist one using "for" loop.... give solution
# 6  
Old 12-28-2011
Code:
i=1;while read x;do echo $x | cut -d" " -f"$i";i=$(($i + 1));done < p

---------- Post updated at 14:27 ---------- Previous update was at 14:23 ----------

Code:
awk 'BEGIN{i=0}++i{print $i}' p

If this is homework, your prof is never gonna believe you wrote these one-liners.
# 7  
Old 12-28-2011
one more .. Just a try .. Smilie
Code:
$ nawk '{print "echo \""$0"\"|cut -d\" \" -f"NR } ' infile | sh

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