Finding max number in filename and opening it


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# 1  
Finding max number in filename and opening it

Hi,

I have files named as

energy.dat.1
energy.dat.2
energy.dat.3
...
energy.dat.2342

I would like to find the file with maximum number in the filename (ex. energy.dat.2342) and open it.

Would you please share your expertize in writing the script?

Thanks in advance.
# 2  
Code:
ls energy.dat.*|sort -rn|head -1

This User Gave Thanks to vbe For This Post:
# 3  
I tried the command. However it gave max file number as 99 (although the folder contains thousands of file)

$ls energy.dat.*|sort -rn|head -1
energy.dat.99

Is there any way to store the file name with maximum number in a variable?
I want to open this file for plotting in octave/gnuplot/python/scilab.

Thanks you.
# 4  
Try this:
Code:
energy.dat.* | awk -F\. 'm<$NF{m=$NF;s=$0}END{print s}'

This User Gave Thanks to Franklin52 For This Post:
# 5  
Quote:
Originally Posted by rpd25
Is there any way to store the file name with maximum number in a variable?
I want to open this file for plotting in octave/gnuplot/python/scilab.
Thanks you.
if you want it to store in a variable , just use the below command:
Code:
max_number=`ls energy.dat.*|sort -rn|head -1`

This User Gave Thanks to pandeesh For This Post:
# 6  
A slight modification to vbe's one-liner:

Code:
ls energy.dat.* | sort -nrk1.12 | head -1

This User Gave Thanks to balajesuri For This Post:
# 7  
Quote:
Originally Posted by balajesuri
A slight modification to vbe's one-liner:

Code:
ls energy.dat.* | sort -nrk1.12 | head -1

Hi,
Could you please explain how that command behaved without key -k specification .
I don't have unix to test it currently

Thanks
This User Gave Thanks to pandeesh For This Post:
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