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mysql query in shellscript

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# 1  
Old 12-19-2011
mysql query in shellscript
Hi,

I want to access mysql query from database , for that i have tried the below code

Code:
#! /bin/bash
TABLE_NAME=database1
USER_NAME=root
IP_ADDR=111.20.9.256
somevar=`echo "select altid from alert where altid='2724'"| mysql -h $IP_ADDR -u $USER_NAME  $TABLE_NAME `
echo $somevar


the above script gives the output

Code:
altid 6


i want the output in somevar is only 6


not altid 6 . how is that ??


Note : please try to change the code only in
Code:
somevar=`echo "select altid from alert where altid='2724'"| mysql -h $IP_ADDR -u $USER_NAME  $TABLE_NAME `

i dont want to increase the line of script becoz same concept i want to apply to many querys .

Please help me .


Thanks
# 2  
Old 12-19-2011
Code:
somevar=$( mysql -h "$IP_ADDR" -u "$USER_NAME"  "$TABLE_NAME" -BNe"select altid from alert where altid='2724'" )

This User Gave Thanks to radoulov For This Post:
aish11
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