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Replace characters in a string using their ascii value

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# 1  
Old 03-03-2005
Replace characters in a string using their ascii value
Hi All,

In the HP Unix that i'm using when i initialise a string as Stalled="'30¬G'"
Stalled=$Stalled" '30¬C'", it is taking the character ¬ as a comma. I need to grep for 30¬G 30¬C in a file and take its count. But since this character ¬ is not being understood, the count returns a zero.
The ascii value of the character ¬ is 188.
I thought of replacing all occurrences of comma using something like
chr(188). But i dont know how to.
Could some one help me or give me some other idea to go about this. I need to do this urgently :-(
Thanks in advance...
# 2  
Old 03-03-2005
Quote:
Originally Posted by roops
Hi All,

In the HP Unix that i'm using when i initialise a string as Stalled="'30¬G'"
Stalled=$Stalled" '30¬C'", it is taking the character ¬ as a comma. I need to grep for 30¬G 30¬C in a file and take its count. But since this character ¬ is not being understood, the count returns a zero.
The ascii value of the character ¬ is 188.
I thought of replacing all occurrences of comma using something like
chr(188). But i dont know how to.
Could some one help me or give me some other idea to go about this. I need to do this urgently :-(
Thanks in advance...
tr '\188' ',' < file
Last edited by vgersh99; 03-03-2005 at 10:05 AM..
# 3  
Old 03-04-2005
Hi vgersh99

Thank u very much for the pointer u gave. But i cracked this problem using grep itself. I said in 30¬G, let the 3rd character(each record in the file starts with 30¬G or 30¬C ) be anything other than zero (since in the file it is alwz ¬ and never zero.) and the fourth character shud be [GC]. From the grep, i got the count..

Thanks anyways coz i learnt what "tr" command is all about. I'm new to unix and my work revolves around unix. So i'm learning Unix while i'm working on live problems. :-)
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