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Awk script to replace null columns with blank

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# 1  
Old 11-28-2011
Awk script to replace null columns with blank
I have a file with contents
Code:
"08011"||20080812
"23348"|20080827|20080924
"23387"|20080829|20080915
"23581"|20081003|20081028
"23748"|20081017|20090114
"24095"|20080919|20081013
"24105"|20070723|20070801
"24118"|20080806|20081013
"24165"|20080820|20080912
"24221"|20080908|20080929

i want to write 10 blanks in case 2 pipes are coming together in the file.
Please help using awk script
Last edited by Franklin52; 11-28-2011 at 03:32 PM.. Reason: Please use code tags for data and code samples, thank you
# 2  
Old 11-28-2011
Code:
sed 's/||/|        |/g' inputfile

Or if you really want to do it in awk:
Code:
awk -F"|" '{ for (i=1;i<=NF;i++) { if ($i=="") { $i="        " } } OFS="|";print }' inputfile

or
Code:
awk '{gsub ("\\|\\|", "|        |"); print}' inputfile

# 3  
Old 11-28-2011
Code:
 
$ sed 's/\|\|/\|          \|/' test
"08011"|          |20080812
"23348"|20080827|20080924
"23387"|20080829|20080915
"23581"|20081003|20081028
"23748"|20081017|20090114
"24095"|20080919|20081013
"24105"|20070723|20070801
"24118"|20080806|20081013
"24165"|20080820|20080912
"24221"|20080908|20080929

# 4  
Old 11-28-2011
Code:
awk 'BEGIN{FS=OFS="|"}{for(i=1;++i<NF;)$i=$i?$i:"        "}1' file

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