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Grep text between multiple pattern


 
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# 1  
Old 10-31-2011
Grep text between multiple pattern

Hello everybody,
I have been looking around but can't figure how to do a grep command, that find the text between multiple patterns, example:

(pattern1 OR pattern2) AND (pattern3 OR pattern4) text that I want (pattern5 OR pattern6) AND (pattern7 OR pattern8)

So how do I find the "text that I want" between <h (and hex equivalent) and i> (and hex equivalent)?
Code:
(<|(%3C))*(h|(%68)) text that I want (i|(%49))*(>|(%3E))

Please give me a grep command.
Thanks so much !
Ben
# 2  
Old 10-31-2011
Can try this one:
Code:
sed 's/.*) \([^)(]\+\) (.*/\1/' infile

# 3  
Old 10-31-2011
try this it worked for me...
Quote:
awk -F ")" '{print $5}' <filename> | awk -F "(" '{print $1}'
# 4  
Old 10-31-2011
Thanks both of you for the quick reply.
However, I do think that sed is the way to go rather than awk.
Would I be able to introduce a OR in sed?
Code:
sed -n '/(<|(%3C))(h|(%68))/,/(i|(%49))(>|(%3E))/p' /path/to/file

Would it be possible to do something like that?
Many thanks!
# 5  
Old 10-31-2011
You did not say if the provided code worked.
A comma between two patterns defines a range and would print out the lines from pattern 1 to pattern 2. This is no OR.

OR (not explicit):
Code:
$> echo xaaax| sed '/\(aaa\|bbb\)/!d'
xaaax
$> echo xbbbx| sed '/\(aaa\|bbb\)/!d'
xbbbx
$> echo xaaabbbx| sed '/\(aaa\|bbb\)/!d'
xaaabbbx


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