Find highest number - working but need help!


 
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# 1  
Old 10-21-2011
Data Find highest number - working but need help!

Hello all, I am new to this and need some help or maybe steer me to the right direction!

I wrote a script to get the highest number and prints it on the screen, the script basically asks the user to input numbers, and then prints the highest number! very simple

it works like this
Code:
$sh max.sh
4 6 8 9
The highest number is: 9

my question is, instead of asking the users for numbers to input, how can i make the script to calculate inputted numbers right away when you execute the script, like this:
Code:
$sh max.sh 6 8 9
The highest number is: 9

please help Smilie

Code:
#!/bin/bash

read num
MAX="0"
for i in $num; do
   if [ $MAX -lt $i ] ; then
   MAX=$(echo $i)
   fi
done
echo "The highest number is: $MAX"

#END

Moderator's Comments:
Mod Comment
Please use code tags when posting data and code samples!

Last edited by vgersh99; 10-21-2011 at 04:13 PM.. Reason: code tags, please!
# 2  
Old 10-21-2011
max.sh:
Code:
#!/bin/bash

typeset -i MAX=0
for ((i=1;i<=$#;i++))
do
   eval a=\$$i
   if [ $a -gt $MAX ] ; then
      MAX=$a
   fi
done
echo "The highest number is: $MAX"

max.sh 8 3 9

Last edited by vgersh99; 10-21-2011 at 04:39 PM..
# 3  
Old 10-21-2011
Thans vgersh99 for the quick reply, unfortunately, i tried your code and get an error

Code:
max.sh: 3: typeset not found
max.sh: 4 Syntax error: Bad for loop variable

Quote:
Originally Posted by vgersh99
Code:
#!/usr/local/bin/bash

typeset -i MAX=0
for ((i=1;i<=$#;i++))
do
   eval a=\$$i
   if [ $a -gt $MAX ] ; then
      MAX=$a
   fi
done
echo "The highest number is: $MAX"

# 4  
Old 10-21-2011
Since you have BASH, just

Code:
MAX=0

.

Also a=${!i}
# 5  
Old 10-21-2011
Can you elaborate a little better!

Quote:
Originally Posted by Corona688
Since you have BASH, just

Code:
MAX=0

.

Also a=${!i}
# 6  
Old 10-21-2011
Instead of typesetting MAX to 0, just do

MAX=0

Instead of using that eval thing, just do

a=${!i} since ${!VAR} returns the contents of the variable named in VAR, not the contents of VAR itself.
This User Gave Thanks to Corona688 For This Post:
# 7  
Old 10-21-2011
I did it like this:

Code:
#!/usr/local/bin/bash

MAX=0
for ((i=1;i<=$#;i++))
do
   a=${!i}
   if [ $a -gt $MAX ] ; then
      MAX=$a
   fi
done
echo "The highest number is: $MAX"

Still throws this error:
Code:
Syntax error: Bad for loop variable

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