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search & replace pattern

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# 8  
Old 10-18-2011
Quote:
Originally Posted by dips_ag
Hi Vgersh,

Thanks for the solution Smilie!!

Can you please explain this sed command ?

-dips
Code:
sed 's#YYYY[^_.]*#*#'

Anything that starts with 'YYYY' followed by anything, BUT '_' or '.' is to be replaced with a '*'.
# 9  
Old 10-19-2011
Hi Vgersh,

Quote:
Originally Posted by vgersh99
I assumed the 'YYYYMMDD' was actually a mnemonic for the date/time numeric spec.
If you want to take 'YYYYMMDD' literally - that's even easier...:
Code:
sed 's#YYYY[^_.]*#*#' myFile

I think I have an additional requirement involving extraction of YYYYMMDD parttern, however what you assumed about this being a mnemonic for data/time data is now true. Can you help me out again?

Code:
 
For e.g.
i/p1: 45_*_20111019_SRC.txt.tar.gz -> o/p: 20111019
i/p2: 201110192359_45_*_SRC.txt.tar.gz -> o/p: 201110192359
i/p3: 45_*_SRC_2011101923.txt.tar.gz -> o/p: 2011101923

I attempted the below code:
Code:
echo 45_*_20111019_SRC.txt.tar.gz | sed 's/.....\(.\{8\}\)\(.*\)/\1/'

but I know this is in vain because it's too much tied up with the length of the string & the pattern length!!
-dips
# 10  
Old 10-19-2011
Quote:
Originally Posted by dips_ag
Hi Vgersh,



I think I have an additional requirement involving extraction of YYYYMMDD parttern, however what you assumed about this being a mnemonic for data/time data is now true. Can you help me out again?

Code:
 
For e.g.
i/p1: 45_*_20111019_SRC.txt.tar.gz -> o/p: 20111019
i/p2: 201110192359_45_*_SRC.txt.tar.gz -> o/p: 201110192359
i/p3: 45_*_SRC_2011101923.txt.tar.gz -> o/p: 2011101923

I attempted the below code:
Code:
echo 45_*_20111019_SRC.txt.tar.gz | sed 's/.....\(.\{8\}\)\(.*\)/\1/'

but I know this is in vain because it's too much tied up with the length of the string & the pattern length!!
-dips
you have to assume a minimum length of numbers to determine if it's a date or not. As your dates may differ in length, I assumed the minimum length of 8 -\{8,\}. Notice the trailing comma in the spec. From man ed:
Code:
       *    An RE followed by:
              \{m\}
                   Matches exactly m occurrences of the character matched by
                   the RE.
              \{m,\}
                   Matches at least m occurrences of the character matched by
                   the RE.
              \{m,n\}
                   Matches any number of occurrences of the character matched
                   by the RE from m to n inclusive.

considering file dip.txt:
Code:
45_*_20111019_SRC.txt.tar.gz
201110192359_45_*_SRC.txt.tar.gz
45_*_SRC_2011101923.txt.tar.gz

the following:
Code:
sed 's#^.*_\([0-9]\{8,\}\)[_.]*.*#\1#;s#_.*##' dip.txt

produces:
Code:
20111019
201110192359
2011101923

This User Gave Thanks to vgersh99 For This Post:
dips_ag
# 11  
Old 10-19-2011
Hi Vgersh,

Simply Superb !!Smilie Thanks again.

-dips
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