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# 1  
Old 10-14-2011
Replace string by file content

hi

I have template file my.tpl:

Code:
bla-bla-bla
<link href="style.css" type="text/css">
bla-bla-bla

and style.css :
Code:
body{margin: 0px;}

I want to get in result one file:
Code:
bla-bla-bla
<script>body{margin: 0px;}</script>
bla-bla-bla

I tryed to used SED:
Code:
sed '/<link .*href=\"([^\"]*)*\" .*>/{
r \1
d
}
' my.tpl > result.tpl

but it was not working.

Help me please. How can I resolve my task with SED or AWK? Thanx.
# 2  
Old 10-14-2011
Code:
egrep -o "<link[^>]+>" < infile > outfile

# 3  
Old 10-14-2011
Quote:
Originally Posted by Corona688
Code:
egrep -o "<link[^>]+>" < infile > outfile

It's find only matched pattern. How can I use it to replace by filename pattern?
# 4  
Old 10-14-2011
Oh, I see... I thought you meant the name of the file for some reason, not a file link.

Code:
$ echo '<link href="style.css" type="text/css">' | sed 's#<link [^>]*type="text/css">#<script>body{margin: 0px;}</script>#g'
<script>body{margin: 0px;}</script>
$

# 5  
Old 10-14-2011
Quote:
Originally Posted by Corona688
Oh, I see... I thought you meant the name of the file for some reason, not a file link.

Code:
$ echo '<link href="style.css" type="text/css">' | sed 's#<link [^>]*type="text/css">#<script>body{margin: 0px;}</script>#g'
<script>body{margin: 0px;}</script>
$

good, thanx. it's work with static content when I know filename.
But script should be work for dynamic files when he don't know css-file name. He should determine css file name and insert css-content directly to tpl-file.
# 6  
Old 10-14-2011
ookay...

What's your system? do you have GNU awk?
# 7  
Old 10-15-2011
My system is Cygwin.
I have AWK on it.

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