Shell Programming and Scripting

Hi i have an input " load /appss/asdfas/...

I want to take the string present between first / / i.e appss

Input is "load /appss/asdfas/..."

Expected output is appss


Thanks in advance
Ananth

Code:

# echo "load /appss/asdfas/..." | awk -F'/' '{print $2}'
appss

Code:

# x="load /appss/asdfas/..."
# t=${x#*/};echo ${t%%/*}
appss

with cut ..

Code:

$ echo "load /appss/asdfas/..." | cut -d'/' -f2

with sed ...

Code:

echo "load /appss/asdfas/..." | sed 's![^/]*/!!;s!/.*!!'

I have a file which has

element * CHECKEDOUT
element \fiosapp\... .../ch_connectedhome/LATEST
element \fiosapp\... /main/LATEST -mkbranch ch_connectedhome
load \fiosapp\ConnectedHome
load \fiosapp\ConnectedHomeProject
load \fiosapp\Build

when i use the command `cat FILE_NAME |grep load |awk -F'\' '{print $2}'`
ConnectedHome
ConnectedHomeProject
Build
are getting printed but i want "fiosapp" to get printed. What do I do??



Thanks
Ananth

Try

Code:

# awk -F'\' '/load/ {print $2}' FILE_NAME
fiosapp
fiosapp
fiosapp

EDIT: But I get that output even with your supplied command. What does the output of your grep command look like? What shell are you using?