Need date in the format [mm dd yyyy hh AM/PM]


 
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# 1  
Old 10-12-2011
Need date in the format [mm dd yyyy hh AM/PM]

could you please help be on the below code ..

Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the [mm dd yyyy hh AM/PM] format Smilie..
Code:
cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()"  | sed '2d'`
pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C\"select dateadd(hh,-$1,getdate())\" | sed '2d'`"
echo "Time period: $pr_dt  - $cur_dt

getting the below output,
Code:
Time period: Oct 11 2011 8:30PM  - Oct 11 2011 10:30PM

Requirement is
Code:
Oct 11 2011 8 PM  - Oct 11 2011 10 PM

(need to exclude the mins)

Last edited by Franklin52; 10-12-2011 at 04:13 AM.. Reason: Please use code tags, thank you
# 2  
Old 10-12-2011
Modify the last line alone..
Code:
$ echo "Oct 11 2011 8:30PM - Oct 11 2011 10:30PM" | sed 's,:.., ,g'
Oct 11 2011 8 PM - Oct 11 2011 10 PM
$

# 3  
Old 10-12-2011
Thanks Jayan ..

below worked for me ..
Code:
sed -e "s/:[0-9]*//g"`


Last edited by Franklin52; 10-12-2011 at 04:13 AM.. Reason: Please use code tags, thank you
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