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file descriptor count

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# 1  
Old 10-04-2011
file descriptor count
I am trying to write a script which will only show me the file descriptor count for a process/pid. My script will return me the count only not the whole output. For example, I would like my script to return the output 23 this case, not the whole output.

Can anybody please help me how do I get the last count only?

Thanks in advance who replies.

HTML Code:
pfiles 18877
 
 
............................................. 
............................................ 
............................................ 
20: S_IFSOCK mode:0666 dev:373,0 ino:47575 uid:0 gid:0 size:0
      O_RDWR FD_CLOEXEC
        SOCK_STREAM
        SO_SNDBUF(49152),SO_RCVBUF(49152),IP_NEXTHOP(0.0.192.0)
        sockname: AF_INET 10.66.36.73  port: 40117
        peername: AF_INET 10.66.36.73  port: 41625
23: S_IFSOCK mode:0666 dev:373,0 ino:31179 uid:0 gid:0 size:0
      O_RDWR|O_NONBLOCK
        SOCK_STREAM
          SO_KEEPALIVE,SO_SNDBUF(49152),SO_RCVBUF(49640),IP_NEXTHO     P(0.0.193.232)
        sockname: AF_INET 10.66.36.152  port: 41627
        peername: AF_INET 10.66.36.174  port: 10000
# 2  
Old 10-04-2011
for my process_id "29141"
Code:
$ pfiles 29141 | awk '/file descriptors/ {print $3}'
256
$

# 3  
Old 10-04-2011
Code:
 pfiles $PID | egrep  '[0-9]+: '|wc -l

or using lsof
Code:
echo $(($(lsof -p $PID |wc -l )-1))

# 4  
Old 10-04-2011
Hi Skrynesaver,

I ran your command but it is not giving me right count... pfiles 18877 has count 23 not 22.

Code:
pfiles 18877 | egrep  '[0-9]+: '|wc -l
      22


Moderator's Comments:
Mod Comment Video tutorial on how to use code tags in The UNIX and Linux Forums.
Last edited by Franklin52; 10-04-2011 at 11:18 AM.. Reason: Please use code tags, thank you
# 5  
Old 10-04-2011
All the command is doing is counting the number of lines which begin " nnn: " (ie start of file descriptor record). Are you sure the number of open files is a constant?

Note in the records you posted above that 21 and 22 are not active FDs for the process. Given FD 0 is the starting point, if all the other potential values are used, then you have 22 FDs for the process.
# 6  
Old 10-04-2011
Here is the command I am trying to run, but it is not working as expected.

If I run pfiles 437 it gives me follwing output and I just want to pick 27 from there...so I ran following command but it prints me the last line instead of the number. Can you see what is wrong with my command?

Code:
 
pfiles 437 | nawk '{print $1}' | nawk '/[0-9]/ {field=$NF} END {print field}' | sed 's/://g'

Code:
 
...........................................
..........................................
...........................................
27: S_IFSOCK mode:0666 dev:373,0 ino:52020 uid:0 gid:0 size:0
      O_RDWR FD_CLOEXEC
        SOCK_STREAM
        SO_SNDBUF(49152),SO_RCVBUF(49152),IP_NEXTHOP(0.0.192.0)
        sockname: AF_INET 0.0.0.0  port: 30901

Code:
 
pfiles 437 | nawk '{print $1}' | nawk '/[0-9]/ {field=$NF} END {print field}' | sed 's/://g'
SO_SNDBUF(49152),SO_RCVBUF(49152),IP_NEXTHOP(0.0.192.0)

# 7  
Old 10-04-2011
Try this...
Code:
pfiles 437 | awk -F":" '/^[0-9]*:/{val=$1} END{print val}'

--ahamed

---------- Post updated at 10:54 AM ---------- Previous update was at 10:54 AM ----------

If solaris, please use nawk!

--ahamed
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