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Trying to take a string and break each letter into a separate variable

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# 1  
Old 10-01-2011
Trying to take a string and break each letter into a separate variable
I am trying to make a script that takes a word and each letter up and turns it into a separate variable. My code currently does not work but I feel I just need to tweak one thing that I am unsure of.

(ex: if forum was typed in letter1=f; letter2=o; letter3=r;...)

Thank you

Code:
count=1;

for i in `echo $1 | sed 's/./& /g'`
do
        echo $i
        letter$count=$i
        count=`expr $count + 1`
done


echo $var1

# 2  
Old 10-01-2011
Hi!
I hope this may help,

Code:
for x in $(seq 1 ${#mystr}) do                
eval "echo letter$x=${mystr:$((x-1)):1}"
done

It uses parameter substitution which is very handy when working with strings, and also some goodies like seq and arithmetics.
Best regards,
Lakris
This User Gave Thanks to Lakris For This Post:
Skrynesaver
# 3  
Old 10-01-2011
The following is kind of what you were going for, though Lakris' example above is why I come to this site, now I can spend Saturday examining the ${#var} (length of var ?)and ${var:$offset:$length} (substring ?) functions.

Code:
#!/bin/bash

for i in $(echo $1 | sed 's/./& /g'); do
        letters[$count]=$i
        count=$(($count+1))
done
for i in $(seq 0 $((${#letters[@]}-1))) ; do
        echo $i letter is ${letters[$i]}
done

Last edited by Skrynesaver; 10-01-2011 at 05:41 AM.. Reason: added length of array notation
# 4  
Old 10-01-2011
Smilie
But all credit should go to where i found it, 10 Steps to Beautiful Shell Scripts .
A wonderful site that can keep You going through sunday as well.

/Lakris
# 5  
Old 10-01-2011
Quote:
Originally Posted by Skrynesaver
The following is kind of what you were going for, though Lakris' example above is why I come to this site, now I can spend Saturday examining the ${#var} (length of var ?)and ${var:$offset:$length} (substring ?) functions.

Code:
#!/bin/bash

for i in $(echo $1 | sed 's/./& /g'); do
        letters[$count]=$i
        count=$(($count+1))
done
for i in $(seq 0 $((${#letters[@]}-1))) ; do
        echo $i letter is ${letters[$i]}
done


When I try to do this, it doesn't save anything into the variables. it leaves them all blank
# 6  
Old 10-01-2011
Quote:
Originally Posted by crimputt
When I try to do this, it doesn't save anything into the variables. it leaves them all blank
Looks good to me. What does your output look like?

Code:
$
$
$ cat -n var.sh
     1  #!/bin/bash
     2
     3  for i in $(echo $1 | sed 's/./& /g'); do
     4          letters[$count]=$i
     5          count=$(($count+1))
     6  done
     7  for i in $(seq 0 $((${#letters[@]}-1))) ; do
     8          echo $i letter is ${letters[$i]}
     9  done
    10
$
$
$ ./var.sh forum
0 letter is f
1 letter is o
2 letter is r
3 letter is u
4 letter is m
$
$
$ echo $SHELL
/bin/bash
$
$

tyler_durden
# 7  
Old 10-01-2011
I am trying to echo out

echo letter1
echo letter2
echo letter3

and it returns nothing


I am unsure about what this does:

for i in $(seq 0 $((${#letters[@]}-1))) ; do
echo $i letter is ${letters[$i]}
done


but it appears that it does not save the letters into seperate variables? Sorry for the confusion
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