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Complex find and replace only 1st instance string with dynamic combination

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# 1  
Old 09-30-2011
Complex find and replace only 1st instance string with dynamic combination
test.txt is the dynamic file but some of combination are fix

like below are the lines
Code:
;wonder_off =
;wonder_off = disabled
wonder_off =
wonder_off = disabled

the test.txt can content them in any order

Code:
#cat test.xt 
;wonder_off =
;wonder_off = disabled
wonder_off =
wonder_off = disabled

OR

Code:
#cat test.xt 
wonder_off =
wonder_off = disabled
;wonder_off =
;wonder_off = disabled

I need to find and replace only 1st instatnce of the test.xt

example if:

Code:
#cat test.xt 
;wonder_off =
;wonder_off = disabled
wonder_off =
wonder_off = disabled

find ";wonder_off =" and replace it with "wonder_off = "Enabled,working_bar,extra_deft""


Result should be :
Code:
cat test.xt 
wonder_off = "Enabled,working_bar,extra_deft"
;wonder_off = disabled
wonder_off =
wonder_off = disabled


I can managed to get only 1st line which can be any combination i mention above
Code:
#VAR=`cat test.xt | head -1`


#echo $VAR
;wonder_off =

How can I Find only 1st instance with matching string and replace it with "wonder_off = "Enabled,working_bar,extra_deft""
Last edited by Scott; 09-30-2011 at 03:30 PM.. Reason: CODE TAGS...
# 2  
Old 09-30-2011
AWK
Hi,
Try this untested code
Code:
awk 'BEGIN{done=0;}$0 ~ /;wonder_off=/{if(done ==0){gsub(/;wonder_off/,";wonder_off=\"Enabled,working_bar\"",$0);done=1;}print;}' file

pls configure substitute string based on your req.
Cheers,
Ranga:-)
# 3  
Old 09-30-2011
replace FILE with your file name :

Code:
sed -i "`grep -n ^\;wonder_off FILE|cut -d':' -f1 |head -1`s/\;wonder_off =/wonder_off = \"Enabled,working_bar,extra_deft\"/" FILE

for reminder, there are two FILE to replace in the code Smilie
# 4  
Old 09-30-2011
Thanks you both

but you missed one VERY IMP thing


the first line can be anything from the combination as i mention
can be
;wonder_off =
can be
;wonder_off = disabled
can be
wonder_off =
can be
wonder_off = disabled
# 5  
Old 09-30-2011
oh, not a problem , just add a $ at the end of grep regex :
Code:
sed -i "`grep -n "^\;wonder_off$" FILE|cut -d':' -f1 |head -1`s/\;wonder_off =/wonder_off = \"Enabled,working_bar,extra_deft\"/" FILE

and its done Smilie
now replace
Code:
;wonder_off

to anything you want to find , and replace
Code:
;wonder_off =

to anything you want to replace.
Last edited by ieth0; 10-01-2011 at 08:19 AM.. Reason: code tags
# 6  
Old 10-01-2011
Code:
$ sed 's,;wonder_off =$,wonder_off = "Enabled\,working_bar\,extra_deft",1' infile

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