Log Analysis with AWK with Time difference

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# 1  
Old 09-20-2011
Log Analysis with AWK with Time difference

I would like to write a shell script that calculated the time difference bettween the log entries. If the time difference is higher as 200 sec. print the complette lines out.
My Problem is, i am unable to jump in the next line and calculate the time difference.

Thank you for your Help.

My log entries in a file:
2011-09-13 16:27:59,334 DEBUG [http-] [domin.a.xy.ade] Start ALG: 0ms
2011-09-13 16:27:59,334 INFO  [http-] [domin.a.xy.ade2123] Used Key156161;

Moderator's Comments:
Mod Comment Please use code tags!

Last edited by radoulov; 09-20-2011 at 03:32 PM..
# 2  
Old 09-20-2011
Hi fabian3010,

Those entries shouldn't be printed because difference between them is 0 seconds, am I right?

# 3  
Old 09-20-2011
I would suggest using perl for date and time arithmetic because doing it in the shell can be very cumbersome and prone to errors.
# 4  
Old 09-22-2011
@berei, thats really right. e.x. in this case is the time difference to high print the two lines on a console.

2011-09-13 16:27:59,334 DEBUG [http-] [domin.a.xy.ade] Start ALG: 0ms
2011-09-13 16:28:01,334 INFO  [http-] [domin.a.xy.ade2123] Used Key156161;

@shamrock do you have an example for me ? in this case ?
# 5  
Old 09-22-2011
But, how many entries are there in the log file? Only two? In case of 11 entries, how should be the output?

I think you sould provide a bigger example to be sure.

# 6  
Old 09-22-2011
Provide a good sample of the input and the expected output...
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