Shell Programming and Scripting

Hi
i am having a shell script reading two arguments.
when the shell script is passed with argument containing $ in it, the value from $ onwards is getting truncated and my script is failing.
i have to do in reading the arguments in the shell script only as i am not having control on the arguments getting passed to the script

Kindly help me.

Code:

test.sh arg$1 arg2

output:

Code:

echo first argument: arg 
echo second argument: arg2

Code:

#!/bin/sh

echo There are $# arguments to $0: $*    
echo first argument: $1    
echo second argument: $2

Kindly hep me in accepting the argument word containing "$" in it

Thanks in advance

You cannot do anything if you have no control on the arguments:
your shell will try to interpret the unquoted special characters before your shell script actually sees them.

what is the character to nullify the '$"

You need to quote it using strong (single) quotes: 'arg$1' or escape it: arg\$1 before passing it to the script.