Shell Programming and Scripting

Code:

 
find . -type f -name "*.xml" | xargs grep -l "pattern"

A few questions itkamaraj

1. The "patterns" in above command line will replace the input file in which I have the list of xml files whose path is to be found. Is that right?

2. The output will be displayed on screen and will not be stored in a file, am I correct?

i misunderstood your problem.

so, you have a text file which has lot of xml files. you need to find out the absolute path of those xml files ?

Code:

 
while read filename
do
         find . -type f -name "$filename" 
done < input.txt

okay, sorry to bother you again, but I am a novice and have a little trouble in getting this script functional.

I created a text file filenames.txt which consists

Code:

connection_words.xml.table
da_sections.xml.table
directory_issue.xml.table
directory_section.xml.table
doc_type.xml.table

And, then I created a script search_full_path.sh like this

Code:

 #!/bin/ksh
 while read filename
do
         find . -type f -name "$filename" 
done < filenames.txt

But when I run this script I get nothing. What am I doing wrong?

replace the . (dot) with the path of the direcotry

Code:

 
find .

. means current directory. it will search the file from the current directory.

so replace . with the directory name which you want to search from.

Thank you so much.
This works just fine!

I appreciate your patience and prompt response!

---------- Post updated at 03:08 PM ---------- Previous update was at 02:47 PM ----------

If I may, can I ask you one more question?

In all the files that I have searched along with their absolute path, there are multiple occurrences of a tag like <DmidRef RefName="GXPRODKEY"/>.

Now my question is how will I enlist all the words within double quotes (like GXPRODKEY) from among all the files that I have just searched.