shell script query

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# 1  
Old 09-13-2011
shell script query

Hi Admins,

I was trying to list the failed logins as part of my daily checklist.
Here is my script
for i in `who -s /etc/security/failedlogins|tail -100|grep "$dt"|awk '{print $1"  "$6}'`
a=`echo $i|wc -l`
if [ $a -gt 0 ]
echo $i
echo "There are no failed logins"

but m getting output in multiple lines.If there are two entries output will be scattered in multiple lines.Please tell me how to print the output in 2 lines(for 2 entries for example). I have used \n with echo $i.. but no use..

new aix

Moderator's Comments:
Mod Comment Use code tags, see PM, thanks.

Last edited by zaxxon; 09-13-2011 at 03:59 PM.. Reason: code tags, see PM
# 2  
Old 09-13-2011

echo "$i"

`who -s /etc/security/failedlogins | tail -100| awk -v dt=$dt ' /dt/ {print $1" "$6}'`

# 3  
Old 09-13-2011

I dont undesrstand why you use "tail -100" ?
You can try this :

who -s /etc/security/failedlogins | awk '    BEGIN {i=0} 
                                            $0 ~ var {print $1" "$6; i++}
                                            END {if (i == 0) print "There are no failed logins"}' var=$dt

# 4  
Old 09-15-2011
thanks for the reply... it has solved my problem..
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