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awk command - not a valid identifier message

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# 1  
Old 09-12-2011
awk command - not a valid identifier message
Trying to run the following awk command :
Code:
export com.mics.ara.server.tools.sch_reports.Runner.num_threads=`awk -F= '!/^#/ && /com.mics.ara.server.tools.sch_reports.Runner.num_threads/{print $2}' $BKUPDIR/env.properties`
 
-bash: export: `com.mics.ara.server.tools.sch_reports.Runner.num_threads=': not a valid identifier

but i'm getting the following error message as per above ?
Last edited by vbe; 09-12-2011 at 12:29 PM.. Reason: code tags
# 2  
Old 09-12-2011
1. Try:
Code:
com.mics.ara.server.tools.sch_reports.Runner.num_threads=1

2. Think about the result.
3. Learn the basics of the shell.
# 3  
Old 09-12-2011
ok my question is :

I have a value within a file :

Code:
aaa.ddd.ccc.ddd.eee.fff=5

how do I create a variable from the above line so I can pass it to another file. But I only need the value 5 as the variable.

thank you

Moderator's Comments:
Mod Comment Please use code tags!
Last edited by radoulov; 09-12-2011 at 01:01 PM..
# 4  
Old 09-12-2011
Code:
$ echo "aaa.ddd.ccc.ddd.eee.fff=5" | awk '{ split($0, A, "="); printf("var=%s\n", A[2]); }'
var=5
$

# 5  
Old 09-12-2011
thank you, now if my line is this below
Code:
 
com.data.ara.reportserver.tools.sch_reports.ReportRunner.num_threads=5

how would I do this ?
Last edited by vbe; 09-12-2011 at 01:11 PM.. Reason: code tags!!! You have been warned...
# 6  
Old 09-12-2011
why don't you apply the same logic as above and try out?

--ahamed
# 7  
Old 09-12-2011
Quote:
Originally Posted by venhart
thank you, now if my line is this below
Code:
 
com.data.ara.reportserver.tools.sch_reports.ReportRunner.num_threads=5

how would I do this ?
Exact same way. It splits on '=' so it ignores everything before the =.
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