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Print text between delimiters IF it contains a certain term...

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# 8  
Old 09-07-2011
It depends, consider that that --- is considered a single dash: -.
It's not regex vs string, it's multi-character/regex vs. single character.
This User Gave Thanks to radoulov For This Post:
vgersh99
# 9  
Old 09-07-2011
If im not wrong, shall we say that all awks support multi-character in RS..?
# 10  
Old 09-07-2011
Consider the following:

Code:
% awk --version | head -1;printf '%s\n' a--b-c | awk 'END { print NR } 1'  RS=--
GNU Awk 4.0.0
a
b-c

2

Code:
$ uname -sr; printf '%s\n' a--b-c | nawk 'END { print NR } 1' RS=--
SunOS 5.8
a

b
c

4


Code:
$ uname -sr; printf '%s\n' a--b-c | /usr/xpg4/bin/awk 'END { print NR } 1' RS=--
SunOS 5.8
a

b
c

4

This User Gave Thanks to radoulov For This Post:
michaelrozar17
# 11  
Old 09-07-2011
Quote:
Originally Posted by michaelrozar17
If im not wrong, shall we say that all awks support multi-character in RS..?
No!

Man nawk on Sun OS:

Quote:
RS The first character of the string value of RS is the
input record separator; a newline character by
default. If RS contains more than one character, the
results are unspecified. If RS is null, then records
are separated by sequences of one or more blank lines:
leading or trailing blank lines do not produce empty
records at the beginning or end of input, and the
field separator is always newline, no matter what the
value of FS.
# 12  
Old 09-07-2011
mawk seems to support regex as RS too:

Code:
% uname -sr; printf '%s\n' a--b-c | mawk 'END { print NR } 1' RS=--
Linux 2.6.38-11-generic
a
b-c

2
% uname -sr; printf '%s\n' a--b-c | mawk 'END { print NR } 1' RS=-+
Linux 2.6.38-11-generic
a
b
c

3

From man mawk on Ubuntu:

Quote:
RS input record separator, initially = "\n".
[...]
RS = " " is not special.
The documentation states:

Code:
mawk splits files into records by the same algorithm, but with the slight difference that RS is really a  termina-
       tor instead of a separator.  (ORS is really a terminator too).

              E.g., if FS = ":+" and $0 = "a::b:" , then NF = 3 and $1 = "a", $2 = "b" and $3 = "", but if "a::b:" is the
              contents of an input file and RS = ":+", then there are two records "a" and "b".

Last edited by radoulov; 09-07-2011 at 11:13 AM..
# 13  
Old 09-09-2011
Thanks radoulov for your kind explanation..
# 14  
Old 09-09-2011
You're very welcome!
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